Alcaraz retains year-end promotion hopes! 2-0 sent Rublev to 2 consecutive defeats, and the final round decisive battle against Zvi

In the second round of the group stage of the ATP year-end finals that ended on the evening of November 13, Beijing time, Spanish genius Alcaraz defeated Russian star Rublev in straight sets and retained the hope of qualifying from the group.

In the first round, Alcaraz lost 0-2 to Ruud and lost to his opponent for the first time in his career. Rublev, on the other hand, also lost 2-0 to Zverev. This game can no longer be lost for both sides. The two have played each other twice before, winning 1 game each.

In the third meeting, the two sides still started very intensely. In the first set, in the first 6 games, the two held serve and fought to 3 draws. After that, Alcaraz, who was playing sickly, began to exert his strength, breaking serve twice in consecutive games in the seventh and ninth games, and finally won three games in a row to win the first set 6-3.

In the second set, both sides held serve in the first 12 games and tied 6. The game was forced into a tie-break, in which Alcaraz fell behind 7-8 at one point. In the end, he scored three points in a row to win the second set tie-break 10-8 and beat Rublev 2-0 on aggregate.

After winning this game, Alcaraz retained his hopes of promotion with a record of 1 win and 1 loss after 2 rounds, while Rublev suffered 2 consecutive defeats and was basically out. In the final round, Alcaraz will play Zverev, while Rublev will play Ruud. Alcaraz will have to fight to beat Zverev to secure the cut.